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Given that:-
- ∠PDA = 30°
- ∠CDQ = 70°
- PQ || RS || TU,
- AB || CD.
To Find:
∠BAD & ∠RAD.
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Let us extend CD to M and AB to N, such that CM || AN.
Here,
∠BAD = ∠BAP + ∠PAD
We can observe from the diagram that,
- ∠BAP = ∠DPS = ∠CDQ (Corresponding Angles)
- ∴ ∠BAP = 70°
And,
- ∠PAD = ∠ODA
- ∴ ∠PAD = 30°
So, ∠BAD = 30° + 70° = 100° (Answer 1)
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Also,
∠RAD + ∠PDA = 180° [Since PQ || RS]
→ x + 30° = 180° [Let ∠RAD = x]
→ x = 180° - 30° → x = 150° (Answer 2).
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