plz koi solve krdooooo plz
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Step-by-step explanation:
In ∆ ABC ,
Sin A= 3/4
I.e,BC/AC= 3/4
i.e,BC= 4k and AC= 3k where k is constant of proportionality.
By Pythagoras theorem,
AB²=AC²-BC²= (4 k)²-(3k²)
Or,AB= √(16-9)k= √7k
hence,tan a= BC/AB= 4K/√7K= 4/√7
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