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AN is parallel to ML and OA is a transversal
so NAD=AOL=17°
in parallelogram angle B=D=133°
in triangle AND
AOL+x= angle D (exterior angle property)
x= 133-17=116°
so NAD=AOL=17°
in parallelogram angle B=D=133°
in triangle AND
AOL+x= angle D (exterior angle property)
x= 133-17=116°
Samotakundu:
wrong
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In parallelogram LMNA,
ML || NA and AD as transversal
therefore,Angle AOL = Angle DAN ---(ALTERNATE ANGLES)
ANGLE DAN =17°---(1)
therefore (x) = 17-180=163
ML || NA and AD as transversal
therefore,Angle AOL = Angle DAN ---(ALTERNATE ANGLES)
ANGLE DAN =17°---(1)
therefore (x) = 17-180=163
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