pls anyone answer ques 15
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ABC is right angle triangle.
so, a^2+b^2=c^2
(a+b)^2-2ab=c^2
(a+b)^2-c^2=2ab
(a+b-c)(a+b+c)=2ab -----------(1)
let r is the radius of circle .
1/2 x r x (a+b+c)=(1/2) x ab
r=ab/(a+b+c)
from equation (1)
r=(a+b+c)(a+b-c)/2 (a+b+c)
=(a+b-c)/2
hence,
r=(a+b-c)/2
so, a^2+b^2=c^2
(a+b)^2-2ab=c^2
(a+b)^2-c^2=2ab
(a+b-c)(a+b+c)=2ab -----------(1)
let r is the radius of circle .
1/2 x r x (a+b+c)=(1/2) x ab
r=ab/(a+b+c)
from equation (1)
r=(a+b+c)(a+b-c)/2 (a+b+c)
=(a+b-c)/2
hence,
r=(a+b-c)/2
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