pls anyone solve ..........
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we have (a^m)^n = a^(mn)
a^m * a^n = a^(m+n)
a^m / a^n = a^(m-n)
a^-m = (1/a^m)
Using all these, answer can be obtained as
[(125x^21)(100x^4)]/128x^42
{5^5 = 125; 10^2 = 100; 2^7 = 128}
[(125*100)/128] (x^25/x^42)
(3125/32)(x^- 17)
= 3125/(32x^17)
;)
Hope it helps
a^m * a^n = a^(m+n)
a^m / a^n = a^(m-n)
a^-m = (1/a^m)
Using all these, answer can be obtained as
[(125x^21)(100x^4)]/128x^42
{5^5 = 125; 10^2 = 100; 2^7 = 128}
[(125*100)/128] (x^25/x^42)
(3125/32)(x^- 17)
= 3125/(32x^17)
;)
Hope it helps
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