Question

pls anyone solve it

Answer 1

solution :
√ 1-cosA/ 1+cosA
=√ (1-cosA)( 1-cosA) /(1+cosA)(1-cosA)
=√(1- cosA) ^2/1- cos^2A
=√ (1-cosA) ^2/ sin^2A
=1- cosA/sinA
=1/sinA -cosA /sinA
=cosecA- cotA
I hope ur will help you

Answer 2

Step-by-step explanation:

RHS :

( cosecA - cotA )²

= ( 1/sinA - cosA/sinA )²

= ( 1 - cosA/ sinA )²

= ( 1 + cosA )²/ sin²A

= ( 1 - cosA )²/ 1 - cos²A

= ( 1 - cosA ) ( 1 - cosA )/ ( 1 + cosA ) ( 1 - cosA )

= 1 - cosA / 1 + cosA

= LHS

∴ Proved

Hope it helps!

If it does then please mark it as brainliest!

Regards,

Soham Patil.