Question

Pls can anyone answer and explain this: A cricketer can throw a ball to a maximum horizontal distance of 100m. The speed with which he throws the ball is ( to thr nearest integer) : a) 30 m/s b)42m/s c) 32m/s d) 35m/s

Answer 1

Given that the ball is thrown to a maximum horizontal distance of 100 meters

The maximum horizontal distance is equal to v to power 2 by g

This implies 100 equals to v to the power by 10

V to the power 2 equals to 1000

Therefore v equals to under root of 1000, this results in 13.6

The speed of the ball is 32m/s

Answer 2

Answer:

Explanation:

Rmax=u$u^{2} sin^{2}theta/g$

as it is thrown horizondally, angle is 90. so sin90=1

so the formula becomes $u^{2} /g$

Rmax=$u^{2}$/10(g is actually 9.8 but take it as 10)

100=$u^{2}$/10

$u^{2}$=1000

u=$\sqrt 1000$

u=31.6≅32m/s