Question

pls clear my doubt....!!
It is given that all three structures are aromatic by huckel rule! and are having 6πe-
1.In the first structure..which lone pair we are considering???
2.In the 2nd one if we are considering the lone pair above the N then we have 6π e- but where as in the third one...only π bond is considered ...why aren't we considering the lone pair in the 3rd structure???
pls spammers stay away!!!!!!!​

Answer 1

Answer:

the lone pair of nitrogen is in sp2 orbital which is perpendicular to the p orbitals of the C=C pi bonds of the ring , so the lone pair cannot go into conjugation with thd pi bonds of the ring , hence it localized and is not counted.

this is also the reason for the basicity of the third structure.. hope it helps..