pls do it as fast as possible....
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Hey Buddy..
Here's the answer..
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=> 3^(2x) + 9 = 10 × 3^( x )
=> ( 3^2 ) × ( 3^x ) + 9 = 10 × 3^( x )
=> 9 × 3^( x ) + 9 = 10 × 3^( x )
=> 9 = 10 × 3^( x ) - 9 × 3^( x )
=> 9 = 3^( x ) [ 10 - 9 ]
=> 9 = 3^( x )
=> 3^(2) = 3^( x )
By comparing
==> x = 2
HOPE HELPED..
JAI HIND
:)
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