Question

pls do this 9th sum.

Answer 1

Let the inner radius be r and the outer radius be R.
2πr = 352
     r = $\frac{352}{2{\pi}}$
2πR = 396
     R = $\frac{396}{2{\pi}}$
Width of track = R - r
                        = $\frac{396}{2{\pi}}$ - $\frac{352}{2{\pi}}$
                        = 7.006  (approximately 7m)
 Area of track = π($R^{2}$ - $r^{2}$)   
                        = π(3976.22 - 3141.71)
                        = 834.51π
                        = 2620.36
Width of track = 7m     
Area of track = 2620.36$m^{2}$