Question

pls evaluate it's from chapter identities ​

Answer 1

Answer:

(x+y+4)²=x² + y² + 16 + 2xy + 8y + 8x

Step-by-step explanation:

(a + b + c)²=a² + b² + c² + 2ab + 2bc + 2ca

here, a=x ; b=y ; c=4; applying identity

⇒ (x+y+4)²=x² + y² + 4² + 2(x)(y) + 2(y)(4) + 2(4)(x)

⇒ (x+y+4)²=x² + y² + 16 + 2xy + 8y + 8x

⇒ (x+y+4)²=x² + y² + 16 + 2xy + 8y + 8x

(If this helped you mark my answer as the brainliest)