pls explain in full steps I have exam tomorrow
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Hence proved ∆ABC=∆DCB
Step-by-step explanation:
In ∆ABC and ∆DCB:
AC=DB (Given)
/_B=/_D*=90°
BC=BC (Common side)
Thus by RHS(Right-angled hypotaneous side) congruency criterion:
∆ABC=∆DCB
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