pls explain in statement
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(a)
= (30×40)-(1/2×30×10)cm^2
= 1200-150
= 1050cm^2
area of shaded region = 1050
(b)
= (40×40)-(1/2×20×40)-(1/2×20×40)
= 1600-(400+400)
= 1600-800
= 800cm^2
area of shaded region = 800
hope this helps u...
= (30×40)-(1/2×30×10)cm^2
= 1200-150
= 1050cm^2
area of shaded region = 1050
(b)
= (40×40)-(1/2×20×40)-(1/2×20×40)
= 1600-(400+400)
= 1600-800
= 800cm^2
area of shaded region = 800
hope this helps u...
Anonymous:
???
Answered by
1
according to figure (a)
first find the area of rectangle ABCD by applying formula (L*B)
=(30*40)=1200cm^2
then find the area of the small triangle ADE by applying the formula 1/2*B*H
=1/2*30*10
=150cm^2
to find thr area of shaded figure subtract the area of rectangle ABCD - the area of trangle ADE
=1200cm^2 - 150cm^2= 1050cm^2
if it helpful plz mark as brainlist and follow me
first find the area of rectangle ABCD by applying formula (L*B)
=(30*40)=1200cm^2
then find the area of the small triangle ADE by applying the formula 1/2*B*H
=1/2*30*10
=150cm^2
to find thr area of shaded figure subtract the area of rectangle ABCD - the area of trangle ADE
=1200cm^2 - 150cm^2= 1050cm^2
if it helpful plz mark as brainlist and follow me
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