pls faaaaaaast class 10 math
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heya it's Aastha.....
◆x^2- ( √5+1)x+√5 =0
◆x^2 - √5x -x + √5 =0
●x ( x- √5) -1 ( x -√5 ) =0
●(x- √5 ) ( x -1) =0
◆x = √5, 1 .
I hope it help you
◆x^2- ( √5+1)x+√5 =0
◆x^2 - √5x -x + √5 =0
●x ( x- √5) -1 ( x -√5 ) =0
●(x- √5 ) ( x -1) =0
◆x = √5, 1 .
I hope it help you
Answered by
1
x^2 - root5x -x + root 5 =0
taking commons
x (x-1) - root 5 (x-1)=0
(x-1)=0 or (x-root5)=0
x=1 or x=root5
taking commons
x (x-1) - root 5 (x-1)=0
(x-1)=0 or (x-root5)=0
x=1 or x=root5
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