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35x²+28x-15x+12=0
7x(5x+4)-3(5x+4)=0
(7x-3) (5x+4)=0
7x-3=0
x=3/7
5x+4=0
x=-4/5
7x(5x+4)-3(5x+4)=0
(7x-3) (5x+4)=0
7x-3=0
x=3/7
5x+4=0
x=-4/5
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0
To get the simplest quadratic, start with factors containing the zeroes. [x - (-3/7)] (x - 2/5) = (x + 3/7)(x - 2/5) = 0 To remove the fractions, multiply both sides of the equation by 7x5, distributing the 7 through the first factor and the 5 through the second factor, and simplify. [7(x + 3/7)] [5(x - 2/5)] = 0 (7x + 3)(5x - 2) = 0
relate this method please i m sooooo lazy to edit this one thaknu
relate this method please i m sooooo lazy to edit this one thaknu
mahi333:
pls find the information pls
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