Math, asked by lalita239, 1 year ago

pls find the answer for 4 th question

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Answered by newton82
1
Given, cos A=5/13 so b=5,h=13 and p=12
sinB=4/5 so p=4,h=5 and b=3
So,
 \sin(a + b)  =  \sin \: a \times  \cos \: b + cos \: a \times sin \: b \\  =   \frac{12}{13} \times  \frac{3}{5} +  \frac{5}{13}   \times  \frac{4}{5}  \\  =  \frac{36}{75} +  \frac{20}{75}   \\  =  \frac{56}{75}
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