Question

Pls find the area of the triangle for the sum given above pls don't give the answer simply explain it step by step if you gave the correct answer I will mark youas brainliest . pls dont spam if you spam i will report your answer and you marks will cut off . pls answer this questions.​

Answer 1

Answer:

the formula is

Step-by-step explanation:

A = √(s(s-a)(s-b)(s-c))

A=7,b=12,c=13

First of all, we need to determine the s, which is the semi-perimeter of the triangle:

s = ½ (a + b + c) = ½ (7 +12 + 13) = 16

Now by inserting the value of the semi-perimeter into the Heron’s formula we can determine the area of the triangle:

A = √(s · (s-a) · (s-b) · (s-c))

A = √(16 · (16-7) · (16-12) · (16-13))

A = √(16 · (9) · (4) · (3))

A = √(1726 ) =

A=41.569 m²

Answer 2

$\sf \Large Solution!!$

The three sides of the triangle are given to us. We can apply Heron's formula to calculate the area of the triangle. But first, we need to find the semi-perimeter. Let's do it!!

side a = 9 cm

side b = 7 cm

side c = 12 cm

Semi-perimeter (s) = $\sf \dfrac{a+b+c}{2}$

s = $\sf \dfrac{9\:cm+7\:cm+12\:cm}{2}$

s = $\sf \dfrac{28\:cm}{2}$

s = 14 cm

We have found the semi-perimeter. Now, we will find out the area.

$\sf Area=\sqrt{s(s-a)(s-b)(s-c)}$

$\sf Area=\sqrt{14(14-9)(14-7)(14-12)}$

$\sf Area=\sqrt{14\times 5\times 7\times 2}$

$\sf Area=\sqrt{980}$

$\sf Area=31.3\:cm^{2}$