Math, asked by rishustudent, 1 year ago

Pls Friends help me please!

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Answered by mintyboba
0

Answer:

you have to rationalise it

1/\sqrt{10} -\sqrt{9}

= 1/\sqrt{10}-\sqrt{9} * \sqrt{10}+\sqrt{9}/\sqrt{10}+\sqrt{9}

=1*(\sqrt{10}+\sqrt{9})/ (\sqrt{10}-\sqrt{9})(\sqrt{10}+\sqrt{9}) -----------#b^{2}

=\sqrt{10}+\sqrt{9}/\sqrt{10} ^{2}-\sqrt{9}^{2}

=\sqrt{10}+\sqrt{9}/10-9-------------##

=\sqrt{10}+\sqrt{9}

Step-by-step explanation:

#-- the (\sqrt{10}-\sqrt{9})(\sqrt{10}+\sqrt{9}) are in form of (a^{2}-b^{2})

##-- the square gets cancelled because of the root

hope it was helpful :)

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