Math, asked by jayadevanbindu78, 10 months ago

pls give answer fast​

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Answered by Mysterioushine
1

Answer:

let the number that should be added be a

then ,

x^4 + 2x^2 -7 + a = 4x^4 - 3x^3 + x^2 + 2

a = 4x^4 -3x^3 + x^2 +2 - x^4 - 2x^2 +7

a = 3x^4 -3x^3 -x^2 +9

Answered by ajay8949
1

let the number should be added be n

(x⁴ + 2x² - 7) + (n) = (4x⁴- 3x³ + x² +2)

n = (4x⁴- 3x³ + x² +2) - (x⁴ + 2x² - 7)

n = (4x⁴- 3x³ + x² +2)-(x⁴+2x²-7)

n = (4x⁴- 3x³ + x² + 2 - x⁴- 2x²+ 7)

n = 4x⁴- x⁴ - 3x³ + x² - 2x² +2 +7

n = 3x⁴ - 3x³ - x² + 9

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