Question

pls give correct answer of this question. 100 points​

Answer 1

Answer:

(y+4)

Step-by-step explanation:

Factorize the first one, we get

(y+3) (y+4)

Second one,

2(y+4)

So, HCF of [(y+3) (y+4)] and [2(y+4)].

HCF is (y+4). Because (y+4) is common in both terms.

For checking,

Let be y=2

Put the y value in given two algebric expressions.

We get 30 and 12

HCF of 30 and 12 is 6. [ans.1]

Put the y value in (y+4)

2+4= 6. [ans.2]

ans.1 and 2 are same.

So, HCF of given expression is (y+4)

Answer 2

(y+4)

Factorize the first one, we get

$(y+3) (y+4)$

Second one,

2(y+4)

So, HCF of [(y+3) (y+4)] and [2(y+4)].

HCF is (y+4). Because (y+4) is common in both terms.

For checking,

Let be y=2

Put the y value in given two algebric expressions.

We get 30 and 12

HCF of 30 and 12 is 6. [ans.1]

Put the y value in (y+4)

2+4= 6. [ans.2]

ans.1 and 2 are same.

So, HCF of given expression is (y+4)