Question

Pls give me the answer ​

Answer 1

AnswEr:-

❀ Your Answer Is $\tt\bf{\dfrac{62}{99}.}$

ExplanaTion:-

To Convert:-

$\\ \tt\longrightarrow0. \bar4 + 0. \overline{18} \: \: \rm \: \: in \: \: \dfrac{p}{q} \: \: form \\ \\ \rm where \: \: p \: \: and \: \: q \: \: are \: \: integers \\ \rm and \: \: q \ne 0.$

So lets first add 0.4 bar and 0.18 bar:-

$\\ \tt\longrightarrow0. \bar4 + 0.\overline {18} \\ \\ \rm = 0.4444.. + 0.1818.. \\ \\ \tt = 0.6262.. \\ \\ \tt = 0.\overline {62}$

Now,

Lets convert 0.62 bar in p/q form:-

For this let 0.62 bar be x.

$\\ \tt\mapsto x = 0. \overline{62}. \\ \\ \tt\mapsto100 \times x = 0.\overline{62} \times 100. \\ \\ \tt\mapsto100x = 62.\overline{62}. \\ \\ \tt\mapsto100x - x = 62.\overline{62} - 0.\overline{62} \\ \\ \tt\mapsto99x = 62. \\ \\ \tt\mapsto x = \frac{62}{99}. \\ \\ \tt\mapsto0.\overline{62} = \frac{62}{99} . \\ \\ \tt\mapsto0. \bar4 + 0.\overline{18} = \frac{62}{99}.$

$\tt\bf{\therefore\ \ 0.\bar4+0.\overline{62}}$ is converted into p/q form where p is 62 and q is 99 also 99 $\tt\bf{\ne}$ 0.