Question

pls give me the answer of question no. 31



urgent

Answer 1

Heya,

Let 3x²-2x = y—————(i)

So, equation becomes,

5-y(6-y)

= 5-6y+y²

= y²-6y+5

= y²-5y-y+5

= y(y-5)-1(y-5)

= (y-5)(y-1)

Putting the value of y in from equation (i.),

(3x²-2x-5)(3x²-2x-1)

= (3x²-5x+3x-5)(3x²-3x+x-1)

= [ x(3x-5)+1(3x-5)][ 3x(x-1)+1(x-1)]

= (3x-5)(x+1)(3x+1)(x-1) Answer...


HOPE IT HELPS:-))