Question

Pls give me the answer using step by step

Answer 1

force applied=100N
frictional force =uN
so frictional force=0.5*10*10=50N
net force =applied-frictional
=100-50=50N
because F=MA
50=10a
so acceleration=5m/s2
I HOPE IT HELP YOU

Answer 2

Given ,
horizontal force F=100N,  
mass of the block m=10Kg,  
coefficient of friction μ=0.5 and 
g=10m/s²

Forces are acting on the block as shown in the diagram. 

Therefore,F−μR=ma,  where a is acceleration produced in 10Kg mass.
And  R=mg. 
Therefore from above two equations, we get,F−μmg=ma.
=> 100−0.5×10×10=10×a.            
=> 100−50=10×a
=> 10×a=50     
=> a=5 m/s²

;)
Hope it helps
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