pls give me the solution
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Answered by
7
Hi there !!
We know that ,
![\sqrt[3]{125} = 5 \sqrt[3]{125} = 5](https://tex.z-dn.net/?f=+%5Csqrt%5B3%5D%7B125%7D++%3D+5)
![\sqrt[3]{0.027} = 0.3 \sqrt[3]{0.027} = 0.3](https://tex.z-dn.net/?f=+%5Csqrt%5B3%5D%7B0.027%7D++%3D+0.3)
and
![\sqrt[3]{0.216} = 0.6 \sqrt[3]{0.216} = 0.6](https://tex.z-dn.net/?f=+%5Csqrt%5B3%5D%7B0.216%7D++%3D+0.6)
So,
![\sqrt[3]{125} + \sqrt[3]{0.027} + \sqrt[3]{0.216} \\ = 5 + 0.3 + 0.6 \sqrt[3]{125} + \sqrt[3]{0.027} + \sqrt[3]{0.216} \\ = 5 + 0.3 + 0.6](https://tex.z-dn.net/?f=+%5Csqrt%5B3%5D%7B125%7D++%2B++%5Csqrt%5B3%5D%7B0.027%7D++%2B+%5Csqrt%5B3%5D%7B0.216%7D+++%5C%5C++%3D+5+%2B+0.3+%2B+0.6)
= 5.9 [ Answer ]
We know that ,
and
So,
= 5.9 [ Answer ]
Anonymous:
:-)
Answered by
1
5.9as cube root of 125 is 5, cube root of 27/1000 = 3/10 and cube root of 216/1000is 6/10 then add these
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