Question

pls... give me the solutions of all the Question pls....

Answer 1

Q find the value of x answers
a)
${2}^{x} + {2}^{x} + {2}^{x} = \: 192 \\ {2}^{x} (3) \: = 192 \\ {2}^{x} = 64 \\ {2}^{x } = {2}^{6 } \\ x = 6$

Answer 2

Q) 3^(x-1)=9
3^(x-1)=3^2
x-1=3===x=3
4^(y+2)=64
4^(y+2)=4^3
y+2=3===y=1

Q)9^x×3^2×3^(-x/2)=1/27
3^(2x)×3^2×3^x=27^(-1)
3^(2x+x+2)=3^(-3)
3^(3x+2)=3^(-3)
3x+2=-3
x=-5/3

hope this will help you