Math, asked by prajakta23184, 20 days ago

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Answered by ayushajaythakare1020
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The area of a square field is 5184 m

2

. Find the area of a rectangular field, whose perimeter is equal to the perimeter of the square field and whose length is twice of its breadth.

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Solution

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Given: area of square =5184m

2

∴ Side of square =

5184

=72m

The perimeter of square =4×72=288m

Let breadth of rectangle =xm

∴ Length of rectangle =2xm

Now, perimeter of rectangle= Perimeter of a square

⇒2(l+b)=288m

⇒2(2x+x)=288

⇒x=

6

288

=48m

∴ Length =2×48=96m, Breadth =48m

Therefore area of rectangle =l×b=96×48=4608m

2

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