pls give the full sol. to the question
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ax³ + bx² + cx + d is exactly divisible by (x + 1) and (x + 2).
means, (x + 1) and (x + 2) are factors of polynomial ax³ + bx² + cx + d .
or, x = -1 and -2 are zeros of polynomial ax³ + bx² + cx + d
at x = -1
a(-1)³ + b(-1)³ + c(-1) + d = 0
-a + b - c + d = 0
c = -a + b + d .......(1)
at x = -2
a(-2)³ + b(-2)² + c(-2) + d = 0
-8a + 4b - 2c + d = 0
from equation (1),
-8a + 4b -2(-a + b + d) + d = 0
-8a + 4b + 2a - 2b - 2d + d = 0
-6a + 2b - 2d + d = 0
-6a + 2b - d = 0
6a - 2b + d = 0
hence, option (D) is correct.
means, (x + 1) and (x + 2) are factors of polynomial ax³ + bx² + cx + d .
or, x = -1 and -2 are zeros of polynomial ax³ + bx² + cx + d
at x = -1
a(-1)³ + b(-1)³ + c(-1) + d = 0
-a + b - c + d = 0
c = -a + b + d .......(1)
at x = -2
a(-2)³ + b(-2)² + c(-2) + d = 0
-8a + 4b - 2c + d = 0
from equation (1),
-8a + 4b -2(-a + b + d) + d = 0
-8a + 4b + 2a - 2b - 2d + d = 0
-6a + 2b - 2d + d = 0
-6a + 2b - d = 0
6a - 2b + d = 0
hence, option (D) is correct.
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In the attachments I have answered this problem.
I have applied remainder theorem to solve this problem.
Remainder theorem:
When p(x) is divided by (x-a) the remainder is p(a)
See the attachment for detailed solution
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