Math, asked by prachibansal1608, 1 year ago

pls give the solution of q-4​

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Answered by s7388
1

let digits are x , y

then number = (10y+x)

x+y = 14 ............(1) equation

(because digit sum is 14)

(10x+y) - (10y+x) = 36..........(2) equation

(because digits get reversed when adding 36)

so, (10x+y) - (10y+x) = 36

x-y = 4 .........(3) equation

from equation 1&3

x= 9 , y= 5

so number will be (10y+x) = 10×5+9 = 59


s7388: thanks for marking as brainliest.
prachibansal1608: welcome
Answered by DynamicPlayer
1

Step-by-step explanation:

Let's take the LCM of 8 and 6 to find the no of girls and boys in the school. i.e =24 then total no.of students in the school is = 24+24=48

Now, total students residing in the hostel={(24×1/8)girls + (24×5/6)boys}= 3 girls + 20 boys . We can say that , 4 boys don't residing in the hostel out of 24 boys and

4 boys don't residing in the hostel out of 48 students. i. e = 4/48= 1/12 boys are not residing in the hostel out of total students in the school

Ans. 1/12.

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