Question

☝️☝️pls give this question answer very very important question of maths with full process​

Answer 1

Given:

• The perimeter of a square is 28 m.

To find:

• The length (side) of the square.
• The area of the square.

Formulae used:

• Perimeter of square = 4s units
• Area of square = s² sq.units

Solution:

The perimeter of a square has been given and we're asked to find its length of side and it's area. In order to find the area, we will require the length of side. So, first we shall find the length of its side by substituting the measure of perimeter in the formula:

$\:\:\:\leadsto{\sf{\purple{Perimeter =4s\:units}}}$

$\\ \:\:\:\:\:\:\:\implies{\bf{28 = 4s}}$

$\\ \:\:\:\:\:\:\:\implies{\bf{\dfrac{28}{4} = s}}$

$\\ \:\:\:\:\:\:\:\implies{\boxed{\frak{\red{7\:m = side}}}}$

$\:$

As we know the length of the square's side, now we can find the area of the square by substituting the measure of side in the formula:

$\:\:\:\leadsto{\sf{\purple{Area =s^2\:sq.units}}}$

$\\ \:\:\:\:\:\:\:\implies{\sf{Area = \bf{7^2}}}$

$\\ \:\:\:\:\:\:\:\implies{\sf{Area= \bf{7\times 7}}}$

$\\ \:\:\:\:\:\:\:\implies{\boxed{\frak{\red{Area = 49\:m^2}}}}$

$\\\therefore\underline{\sf{The\: length\:of\:side\:of\:the\:square\:is\:\bf{\blue{7\:m}}\sf\:and\:the\:area\:of\:the\:square\:is\:\bf{\blue{49\:m^2}}\sf{.}}}$

_____________________________________________

Some formulae for AREA:-

$\\\:\:\:\sf{\bullet\: Trapezium=\dfrac{1}{2}h(sum\: of\: parallel\:sides)\:sq.units}$

$\\\:\:\:\sf{\bullet\: Parallelogram=bh\:sq.units}$

$\\\:\:\:\sf{\bullet\: Rhombus=\dfrac{1}{2}d_1d_2\:sq.units}$

$\\\:\:\:\sf{\bullet\: Rectangle=lb\:sq.units}$

$\\\:\:\:\sf{\bullet\: Circle=\pi r^2\:sq.units}$

$\\\:\:\:\sf{\bullet\: Semi\: circle=\dfrac{1}{2}\pi r^2\:sq.units}$

Answer 2

Step-by-step explanation:

Perimeter = 4 x side

28 = 4 x side

side = 28 ÷ 4

side = 7m

Area = side x side

Area = 7 x 7

Area = 49m