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Answers
Step-by-step explanation:
two concentric circle with centre 'O'.
AD
is the chord of the bigger circle.
AD
intersect the smaller circle at B and C.
Construction: Draw
OE
perpendicular to
AD
Proof: AD is the chord of the bigger circle with centre 'O' and
OE
is perpendicular to
AD
.
∵
OE
bisects
AD
(The perpendicular from the centre of a circle to a chord bisect it)
∴AE=ED ....(i)
BC
is the chord of the smaller circle with centre 'O' and
OE
is perpendicular to AD.
∵
OE
bisects
BC
(from the same theorem)
∴BE=CE .... (ii)
Subtracting the equation (ii) from (i), we get
AE−BE=ED−EC
AB=CD
solution
Answer ByavatarToppr
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