Question

pls guys solve this question




there is a big bigggg points pls solve this


don't write wrong answer
otherwise I report ed

Answer 1

Merry Christmas !

$\mathfrak{\underline{\huge{Solution : }}}$

Let the 2-digit number be = 10x + y

Sum of the digits = 7
x+y=7

x=7-y ...........(1.)

When the 2-digit number will be reversed = 10y
+ x

Now, According to the question

10y + x = 4(10x + y) - 3

10y + x = 40x + 4y - 3

10y - 4y + = 40x - x - 3

6y = 39x - 3

6y = -(39x + 3 )

39x - 6y = 3

3(13x - 2y)=3

13x - 2y = 1 ...........[put eq (1.) in it]

13(7-y) - 2y = 1

91 - 13y -2y = 1

$\cancel{-}$15y = $\cancel{-}$90

y = 90 / 15

y = 6

x = 7 - 6 = 1

So, the original 2-digit number is -

=10x + y

=10(1) + 6

=10 + 6

=16

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☯✳HOPE IT HELPS✳☯

Answer 2

Answer:

Step-by-step explanation:

Let the 2-digit number be = 10x + y

Sum of the digits = 7

x+y=7

x=7-y ...........(1.)

When the 2-digit number will be reversed = 10y

+ x

Now, According to the question

10y + x = 4(10x + y) - 3

10y + x = 40x + 4y - 3

10y - 4y + = 40x - x - 3

6y = 39x - 3

6y = -(39x + 3 )

39x - 6y = 3

3(13x - 2y)=3

13x - 2y = 1 ...........[put eq (1.) in it]

13(7-y) - 2y = 1

91 - 13y -2y = 1

15y = 90

y = 90 / 15

y = 6

x = 7 - 6 = 1

So, the original 2-digit number is -

=10x + y

=10(1) + 6

=10 + 6

=16

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