Question

pls helme to solve this question

Answer 1

let the current population be x and in time n the population is 2x
after 1yr population is x(1+39.4/1000)(1-19.4/1000) =y
after 2 yrs population is y(1+39.4/1000)(1-19.4/1000)
= x(1+39.4/1000)²(1-19.4/1000)²
.
.
.
 after n years
x(1+39.4/1000)ⁿ(1-19.4/1000)ⁿ=2x
 n = ㏒ 2/(㏒ 1.0394 + ㏒0.9806)
using log tables,
log 1.0394 = 0.0166
log 0.9806 = -0.008
log 2 = 0.3010
n= 35yrs

f88e4121d4e1f194b71e1402bd0fa8e2.pdf