Question

Pls. help

A piece of iron ore contains a compound containing 72.3% iron and 27.7%oxygen with a molecular mass of 231.4 g/mol.What is the molecular formula of the compound.
Pls no spams.​

Answer 1

Answer:

Fe3O4

Explanation:

72.3% of Iron (Fe) have 231.4g/mol molecular weight,

so,

(72.3/100)*231.4

= 167.3

and for Oxygen,

27.7% of 231.4 is,

(27.7/100)*231.4

= 64.09

we know that,

atomic mass of iron is 55.84u

so,

167.3/55.84 is

= 3

Similarly for Oxygen (atomic mass=16u),

64.09/16

= 4

so, there are 3 Fe atoms and 4 Oxygen atoms,

and the compound is,

Fe3O4