pls help frnds..?...... fast
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Answered by
6
Heya!!
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= 1/3 x^2 + 1/2 x + 2 - (x^2 - 5/2 x + 7)
= 1/3 x^2 + 1/2 x + 2 - x^2 + 5/2 x - 7
= 1/3 x^2 - x^2 + 1/2 x + 5/2 x + 2 - 7
= - 2/3 x^2 + 6/2 x - 5
= - 2/3 x^2 + 3x - 5
Hope it helps uh :)
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= 1/3 x^2 + 1/2 x + 2 - (x^2 - 5/2 x + 7)
= 1/3 x^2 + 1/2 x + 2 - x^2 + 5/2 x - 7
= 1/3 x^2 - x^2 + 1/2 x + 5/2 x + 2 - 7
= - 2/3 x^2 + 6/2 x - 5
= - 2/3 x^2 + 3x - 5
Hope it helps uh :)
Answered by
2
Given Equation is x^2 - (5/2)x + 7 ----- (1)
Given Equation is (1/3)x^2 + (1/2)x + 2 ---- (2)
Subtract (1) from (2), we get
= > x^2/3 + (x/2) + 2 - (x^2 - 5x/2 + 7)
= > x^2/3 + (x/2) + 2 - x^2 + 5x/2 - 7
= > (x^2/3) - x^2 + 3x - 5
= > (-2x^2 + 9x)/3 - 5
= > (-2x^2 + 9x - 15)/3
Hope this helps!
siddhartharao77:
:-)
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