Question

pls help i attac/hed imaje i am in exam fast plea/se pl/ease pl/ease h/elpp/p/p ppppp pp mee eee

I above attached I ma de I you know two ans write that in app per and sent if you know anyone sent that please​

Answer 1

Answer:

Let the hashita's age be 3x and sana's age be 4x

Then eight years from now means 3x + 8 = 4x + 8

4x + 3x = 7x = 8 + 8 = 16

7x = 16

x = 16/7

Step-by-step explanation:

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Answer 2

Answer:

Answer:

The present ages of Hashira and Sana are 12 years and 16 years respectively.

Step-by-step explanation:

Given :

Present age Ratio = 3 : 4

Ratio of ages after 8 years = 5 : 6

To find :

Their present ages

Solution :

Let the present ages be -

Hashira as 3y

Sana as 4y

Ages after 8 years -

Hashira = (3y + 8)

Sana = (4y + 8)

According to the question,

Hashira and Sana after 8 years have their age Ratio as 5 : 6

$\boxed{\tt{\frac{3y + 8}{4y + 8} = \frac{5}{6}}}$

4y+8

3y+8

=

6

5

$\begin{gathered}\tt{\longrightarrow} \: \dfrac{3y + 8}{4y + 8} = \dfrac{5}{6} \\ \\ \tt{\longrightarrow} \: 6(3y + 8) = 5(4y + 8) \\ \\ \tt{\longrightarrow} \: 18y + 48 = 20y + 40 \\ \\ \tt{\longrightarrow} \: 20y - 18y = 48 - 40 \\ \\ \tt{\longrightarrow} \: 2y = 8 \\ \\ \tt{\longrightarrow} \: y = \dfrac{8}{2} \\ \\ \tt{\longrightarrow} \: y = 4\end{gathered}$

⟶

4y+8

3y+8

=

6

5

⟶6(3y+8)=5(4y+8)

⟶18y+48=20y+40

⟶20y−18y=48−40

⟶2y=8

⟶y=

2

8

⟶y=4

\rule{300}{0.5}

★ Hashira's present age -

$\begin{gathered}\tt{\longrightarrow} \: 3(4)\\ \\ \tt{\longrightarrow} \: 12\end{gathered}$

⟶3(4)

⟶12

Hashira is 12 years old.

\rule{300}{0.5}

★ Sana's present age -

$\begin{gathered}\tt{\longrightarrow} \: 4(4) \\ \\ \tt{\longrightarrow} \: 16\end{gathered}$

⟶4(4)

⟶16

Sana is 16 years old.

∴ The present ages of Hashira and Sana are 12 years and 16 years respectively.

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