Question

pls help i have a test tomoroow​

Answer 1

Answer:

Draw CG ¦DF In ΔBDF

CG ¦ DF

∴ BD/CD = BF/GF .............(1) BPT

In ΔAFE

∠AEF=∠AFE

⇒AF=AE

⇒AF=AE=CE..............(2)

In ΔACG

E is the mid point of AC

⇒ FG = AF

∴ From (1) & (2)

BD/CD = BF/CE

Hence proved