Question

pls help in question ​

Answer 1

Answer:

answer is 57

Step-by-step explanation:

to get 12 by addition the possible combinations of single digit no are

1) 9+3, 3+9 difference here is not 18

2) 8+4, 4+8 difference here is not 18 either

3)7+5, 5+7 difference here is 18 and 18 has to be found by addition so the no is 57

if want to do by formula

there is relation when we interchange a two digit no

if we interchange a 2 digit no "ab" to "ba " the difference would be 9(a-b) to get sum 11(a+b)

eg 72 and 27 difference is 9(7-2) = 9*5= 45

here it is given that difference is 18, and sum is 12

a+ b=12.....eq1

9(a-b)= 18, ie a - b = 3.....eq2

solving we get 2a =14 ie a = 7 ,b =5 ie no is either 75/57

since u have to add 18 to get the reversed no here the answer is 57.

Answer 2

SOLUTION:-

Given:

•The sum of the digits of a two digit number is 12.

•The number obtained by interchanging the two digits exceeds the given number by 18.

To find:

The number.

Explanation:

Assume the digits be R & M.

R+M= 12

R= 12-M............(1)

The two digits number is 10R +M

Interchanging number= 10M+R

According to the question:

=) 10R +M+18= 10M+R

=) 10R -R+M-10M= 18

=) 9R -9M= 18

=) R -M= 2

=) 12-M-M= 2

=) 12-2M= 2

=) -2M= 2 -12

=) -2M= -10

=) M= -10/-2

=) M= 5

&

R= 12-5

R= 7

Interchanging number:

=) 10M+R

=) 10(5) +7

=) 50 +7

=) 57

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