Question

Pls help in this question

Answer 1

HEYA!!

Your solution is in the attachment.

#KEVIN
HOPE IT HELPS YOU ☺

Answer 2

Hola Friend ✋✋✋

Your answer is

LHS :

$\frac{ {tan}^{2} a + 1}{ {tan}^{2}a } \times \frac{ {cot}^{2} a + 1}{ {cot}^{2} a} \\ \\ = \frac{ {sec}^{2}a }{ {tan}^{2} a} \times \frac{ {cosec}^{2}a }{ {cot}^{2} a} \\ \\ = {sec}^{2} a \times {cosec}^{2} a$


RHS :

$\frac{1}{ {sin}^{2}a - {sin}^{4} a } \\ \\ = \frac{1}{ {sin}^{2}a \times (1 - {sin}^{2} a) } \\ \\ = \frac{1}{ {sin}^{2}a \times {cos}^{2} a } \\ \\ = {cosec}^{2} a \times {sec}^{2} a$
Therefore LHS = RHS

Hope it helps