Question

pls help in this question

Answer 1

Answer:

i) uniform acceleration

Explanation:

i) OA ↔ uniform acceleration

  BC ↔ uniform retardation

ii) Time during which car moves with constant veo = 10 - 2 = 8 s

iii) Between 3rd and 10th sec body is moving with uniform velocity

   ∴ acceleration a = 0

iv) Distance travelled = Area under Vt graph

                                   = (1/2 X 2 x 6) + (8 x 6)

                                   = 6  + 48

                                   = 54 m