Math, asked by gunadharshini, 5 hours ago

pls help m to do the 6th sum pls..
some one answer it​

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Answers

Answered by anchalchoudhary202
0

Answer:

hii how are you all

Step-by-step explanation:

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Answered by samaira173
0

Answer:

15 and 25

Step-by-step explanation:

let the common ratio be x

ATQ, (3x+5)/(5x+5)=2/3

so, (3x+5)*3=2*(5x+5)

9x+15=10x+10    [or 10x+10=9x+15]

10x-9x=15-10

x=5

original numbers are 3x and 5x

i.e., 3*5 and 5*5

i.e., 15 and 25

hence, the required original numbers are 15 and 25.

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