Question

Pls help me how to do this question

Answer 1

Answer:

It's very simple Bro.

Explanation:

Just first apply the formula of volt that is v= I ×r and then take out the resistance by formula 1/r = 1/r1 + 1/r2 + 1/r3 + 1/ r4 + 1/r5 and when you take out all these then apply the formula of I = v×r.

Answer 2

Answer

1 Ampere.

Explanation

First of all, as we can see, Resistance between BC and CD are in series. Hence, solve them first

→ 3 ohm + 3 ohm = 6 ohm

Now, this means that two resistances of 3 ohm can be simplified to one resistance of 6 ohm.

Now, this 6 ohm resistance will be parallel to the resistance of 3 ohm (between BD)

→ solve the parallel combination

1/6 + 1/3 = 1/R

(R = equivalent resistance)

→ 3/6 = 1/R

→ R = 2 ohm

Now, this means that the resistance of 3 ohm in the circuit BCD, can be simplified to resistance of 2 ohm between BD.

Now, this 2 ohm would be in series with resistance between AB and DE

→ total resistance = 0.5 + 2 + 0.5 ohm

→ Total resistance = 3 ohm

Now, total resistance of the circuit = 3 ohm.

→ Current, I = V/R

Given, V = 3 V

R = 3 ohm (simplified above)

→ I = 3/3 = 1 A.

Hence, ammeter will show a reading of 1 A.