Question

pls help me in maths

IN A H.P 4th term is 1/9 and 13th term is 1/27 then the 8th term is ​

Answer 1

8th term is 19/243

$a_{4} = a_{} + 3d \: = \frac{1}{9} \\a_{13} = a_{} + 12d \: = \frac{1}{27}$

Subtracting Both

$a + 3d - a - 12d = \frac{1}{9} - \frac{1}{27} \\ - 9d = \frac{3 - 1}{27} \\ - d = \frac{2}{27 \times 9} \\ - d = \frac{2}{243} \\ d = - \frac{2}{243}$

$a_{4} = a_{} + 3d \: \\ \frac{1}{9} = a + 3( - \frac{2}{243} ) \\ \frac{1}{9} = a - \frac{2}{81} \\ a = \frac{1}{9} + \frac{2}{81} \\ a = \frac{9 +2}{81} \\ a = \frac{11}{81}$

So

a = 11/81

d = -2/243

$a_{8} = a_{} + 7d \: \\ a_{8} = \frac{11}{81} + 7( - \frac{2}{243}) \: \\ a_{8} = \frac{11}{81} - \frac{14}{243} \\ a_{8} = \frac{33 - 14}{243} \\ a_{8} = \frac{19}{243}$

if possible please mark it as Brainliest

Answer 2

Step-by-step explanation:

Be Happy❤

&ˣ ᵐ€€ᵗ