Question

Pls .. Help me in solving this now X²+(3-√2)x-3√2=0

Answer 1

${x}^{2} - (3 - \sqrt{2} )x - 3 \sqrt{2} = 0 \\ {x}^{2} - 3x + \sqrt{2} x - 3 \sqrt{2} = 0 \\ x(x - 3) + \sqrt{2} (x - 3) = 0 \\ (x - 3)(x + \sqrt{2} ) = 0 \\ x = 3 \\ x = - \sqrt{2}$

hope it helps