Question

pls help me in solving this problem...

Answer 1

Answer:

Step-by-step explanation:

(1)AREA OF ΔPQR=1/2*BASE*HEIGHT

=1/2*PQ*RT

=1/2*4*6

=12CM²

(2)

AREA OFΔPQR BE SAME ON TAKING ANY BASE HEIGHT IN Δ

SO,AREA OF ΔPQR=1/2*PR*QS

12=1/2*8*QS

SO,12=4QS

QS=12/4

QS=3CM