Question

pls help me its urgent

Answer 1

The solution of the question is in the attachment.

Answer 2

Answer:

Required value of a^4 + 1 / a^4 is 322.

Step-by-step explanation:

It is given that the numeric value of a is not equal of 0.

Also, a - 1 / a = 4

Square on both sides of ( a - 1 / a = 4 ) : -

= > ( a - 1 / a )^2 = 4^2

From the properties of expansion : -

• ( a - b )^2 = a^2 + b^2 - 2ab

Thus,

= > ( a )^2 + ( 1 / a )^2 - 2( a x 1 / a ) = 16

= > a^2 + 1 / a^2 - 2( 1 ) = 16

= > a^2 + 1 / a^2 - 2 = 16

= > a^2 + 1 / a^2 = 16 + 2

= > a^2 + 1 / a^2 = 18

Again square on both : -

= > ( a^2 + 1 / a^2 )^2 = 18^2

= > ( a^2 )^2 + ( 1 / a^2 )^2 + 2( a^2 x 1 / a^2 ) = 324

= > a^4 + 1 / a^4 + 2( 1 ) = 324

= > a^4 + 1 / a^4 + 2 = 324

= > a^4 + 1 / a^4 = 324 - 2

= > a^4 + 1 / a^4 = 322.

Hence the required value of a^4 + 1 / a^4 is 322.