Question

pls help me out...... ........​

Answer 1

Step-by-step explanation:

$( {x}^{2} + \frac{1}{25 {x}^{2} }) = 8 \frac{3}{5} = > {x}^{2} + \frac{1}{25 {x}^{2}} +$

$2 \times x \times \frac{1}{5x} = \frac{43}{5} + \frac{2}{5} = > {(x + \frac{1}{5x})}^{2} =$

$9 = > (x + \frac{1}{5x}) = \sqrt{9} = 3$

(i) The value of (x +1/5x) is 3.

${x}^3 + \frac{1}{125 {x}^3 } = (x + \frac{1}{5x})( {x}^{2} + \frac{1}{25 {x}^{2} } - \frac{2}{5})$

$= > {x}^3 + \frac{1}{125 {x}^{3} } = 3( \frac{43}{5} - \frac{2}{5}) = \frac{123}{5}$

Hope it helps you.