Question

Total number of electrons in 6.2mg NO3-​

Answer 1

Explanation:

The no. of electrons in a molecule of NO3- =

7+3(8)+1 =32. Moles present in 6.2 mg of NO3- =>(6.2/1000)/62=>0.0001. Since 1 mole has 6.022×10^23 particles such as atoms or molecules. Hence 6.2 mg of NO3- has 6.022×10^23×0.0001×32 =>192.704×

10^19 electrons =>1.927×10^21 electrons. So 6.2 mg of NO3- has 1.927×10^21 electrons. Hope it helps you.