Question

pls help me out
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Answer 1

Given-

p(x) = 2x²+(3k-2)x+k

2 is zero of p(x).

To find-

Value of k

Solution-

p(x) = 2x²+(3k-2)x+k

2 is zero of p(x).

Therefore, p(2) = 0.

2(2)²+(3k-2)2 + k = 0

8 + 6k - 4 + k = 0

4 + 7k= 0

7k= -4

k= -4/7