Pls help me out question no 19
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speed=0.7m/s
r=40cm=0.4m
d=2cm=0.02m
t=30min=30*60=1800sec
height of water raised be h
vol.of water passing in 1800sec=vol.of water in vsl
dstnce =speed*time
0.7*1800
1260m
as per qstn now
πr²d=πr²d
3.14*0.01*0.01*1260=3.14*0.4*0.4*h
3.14 get cancelled
0.126=0.16*h
h=0.7875m
r=40cm=0.4m
d=2cm=0.02m
t=30min=30*60=1800sec
height of water raised be h
vol.of water passing in 1800sec=vol.of water in vsl
dstnce =speed*time
0.7*1800
1260m
as per qstn now
πr²d=πr²d
3.14*0.01*0.01*1260=3.14*0.4*0.4*h
3.14 get cancelled
0.126=0.16*h
h=0.7875m
Anonymous:
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