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a) 3 square metre of paint will be needed
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hiii!!!!
here's ur answer...
given the height (length) of the door is 1.5m and breadth (wide) is 2m.
area of the door = l×b
= 1.5×2
= 3m²
length (height) of the wall excluding the triangular part = 2.5m
Breadth of the wall = 3.5m
area of the wall excluding the triangular part = l×b
= 2.5×3.5
= 8.75m²
now, area of the triangular part = 1/2×b×h
= 1/2×3.5×1.2
= 3.5×0.6
= 2.1m²
total area of the wall = 8.75+2.1
= 10.85m²
area of the wall excluding door = 10.85-3
= 7.85m²
a. 7.85m² of paint will be needed
b. if a can covers 2.5m² then no of cans needed to cover the wall = 7.85/2.5
= 3.14 cans is required
c. cost of 1 can = $24.50 then total cost = 3.14×24.50
= $76.93
hope this helps..!
here's ur answer...
given the height (length) of the door is 1.5m and breadth (wide) is 2m.
area of the door = l×b
= 1.5×2
= 3m²
length (height) of the wall excluding the triangular part = 2.5m
Breadth of the wall = 3.5m
area of the wall excluding the triangular part = l×b
= 2.5×3.5
= 8.75m²
now, area of the triangular part = 1/2×b×h
= 1/2×3.5×1.2
= 3.5×0.6
= 2.1m²
total area of the wall = 8.75+2.1
= 10.85m²
area of the wall excluding door = 10.85-3
= 7.85m²
a. 7.85m² of paint will be needed
b. if a can covers 2.5m² then no of cans needed to cover the wall = 7.85/2.5
= 3.14 cans is required
c. cost of 1 can = $24.50 then total cost = 3.14×24.50
= $76.93
hope this helps..!
Anonymous:
is my answer correct??
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